Question

The sum of four consecutive numbers in A. P. is 32 and the ratio of the product of the first
and last terms to the product of two middle terms is 7:15. Find the number.
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Answer 1

Answer:

7.25

Step-by-step explanation:

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Answer 2

Answer:

2,6,10,14

Step-by-step explanation:

let the numbers be a-3d,a-d,a+d and a+3d

then their sum = 4a = 32.

==> therefore, a=8          

(a-3d)(a+3d) / (a-d)(a+d)  = 7  / 15

=> a^2 - 9d^2 / a^2 - d^2 = 7/15

=> solving this gives,

8 * a^2 =  128 *d^2

substitute the value of a to get d=2

then the numbers are 8-6, 8-2, 8+2, 8+6

=> 2,6,10,14