The sum of four consecutive numbers in an ap is 32 and the ratio of the product of first and last term to the product of the two middle term is 7:15. Find the numbers.
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Answer:
Let the numbers be a-3d, a-d, a+d , a+3d
Step-by-step explanation:
Then,
a-3d +a-d+a+d+a+3d = 32
4a=32
a = 8
Then,
a-3d / a+3d = 7/15
8 - 3d/ 8+3d = 7/15
120 - 45d = 56 + 21d
64 = 66d
d = 32/33
Put the va;ues to get the answer
drisya48:
I think this can't be correct.
This is not correct umm they saud the product of first and last that will a^2 -9d^2/ a^2 -d^2 =7/15 i think u will get d is equal to +-2...your a is correct
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Hey mate!
here is your answer
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Yeah dis is right
^_^
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