Question

the sum of four consecutive numbers in an ap is 32 and the ratio of the product of the first and last term to the product of the two middle term is 7 ratio 5 find the number​

Answer 1

Answer:

Step-by-step explanation:

Let the four consecutive numbers in AP be a-3d,a-d,a+d,a+3d.

So,

       a-3d+a-d+a+d+a+3d=32

       4a=32

       a=8 1

       (a-3d)(a=3d) / (a-d)(a+d)=7/15

       15(a2-9d2) = 7(a2-d2)

        15a2-135d2 = 7a2-7d2

         8a2-128d2 = 0

         d2 = 4, ±2

Therefore d=4  or d=±2 1mark

So, when a=8 and d=2, the numbers are 2,6,10,14.

When a=8,d=-2 the numbers are 14,10,6,2

Answer 2

correct answer...you can take any 4 terms as consecutive