The sum of four consecutive numbers in ap os 32 and ratio of products of first term to product of two middle terms is 7:15
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Step-by-step explanation:
let the four consecutive term be
a-d , a, a+d ,a+2d
first condition
a-d+a+a+d+a+2d=32
-d and +d has been cancelled
4a+2d=32
take 2 common
2(2a+d)=32
2a+d=16........ ........... ........... ( i )
second condition
a-d : a(a-d) =7:15
a-d /a^2-ad=7/5
5(a-d) =7(a^2-ad)
5a-5d=7a^2-7ad.......ii
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