Question

The sum of four consecutive numbers ina AP is 32 and the ratio of the product of the first and the last terms to the product of the two middle terms is 7:15

Answer 1

case 1st :-
when a = 8, d = 2
1. a-3d = 8 - 3 × 2 = 8 - 6 = 2
2. a - d = 8 - 2 = 6
3. a + d = 8 +2=10.
4. a + 3d = 8 + 3 × 2 = 8 + 6 = 14

case 2nd :-
when a = 8, d = -2
1. a - 3d = 8 - 3 × -2 = 14
2. a -d = 8 - (-2) = 10
3. a + d = 8 -2 = 6
4. a + 3d = 8 + 3 × -2 = 2

Answer 2

a=6.5 what we have to find right question clearly