Question

The sum of four consecutive numbers is 230. find them.

Answer 1

let the no.s be x ,x+1,x+2,x+3
x+x+1+x+2+x+3=230
4x+6=230
4x=230-6
4x=224
x=224÷4
x=56 1st no=56
2nd no=56+1=57
3rd no=56+2=58
4th no=56+3=59

Answer 2

$\huge\mathfrak\green{Answer:}$

Given:

• We have been given that the sum of four consecutive numbers is 230.

To Find:

• We need find the four consecutive numbers.

Solution:

Let the numbers be (x), (x + 1), (x + 2) and (x + 3).

Now, it is given that the sum of these four consecutive numbers is 230. Therefore,

(x) + (x + 1) + (x + 2) + (x + 3) = 230

=> 4x + 6 = 230

=> 4x = 230 - 6

=> 4x = 224

=> x = 224/4

=> x = 56

x = 56

x + 1 = 56 + 1 = 57

x + 2 = 56 + 2 = 58

x + 3 = 56 + 3 = 59

Hence, four consecutive numbers are 56, 57, 58 and 59.