Question

the sum of four consecutive numbers is 98. let the first number be x and write down the other three numbers in terms of x. find the four numbers. Pls answer quickly guys, I have only 20 minutes.... ​

Answer 1

Answer:

Let the first odd number be x. 

Thus, the other consecutive numbers are x+2,x+4,x+6

Now, given that sum of all four numbers is 40,

x+x+2+x+4+x+6=40

⇒4x+12=40

⇒4x=28

⇒x=7

Thus, the smallest number 7.

Answer 2

Step-by-step explanation:

let the four numbers be x, x+1, x+2, x+3.

we know that their sum is 98

x+x+1+x+2+x+3 = 98

4x = 98 - 6

4x = 92

x = 92/4

x = 13 (first number)

x + 1 = 14 (second number)

x+2 = 15 (third number)

x+3 = 16 (fourth number)

hope it helps❤