The sum of four consecutive odd natural numbers is 136. Find the largest of these numbers.
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Let the no. be z , z+1 , z+2 , z+3
Addind all, we get, z+z+1+z+2+z+3
=4z + 6
ATQ, 4z + 6 = 136
=> z = 32.5
The largest no. is 32.5+3 = 35.5
Answered by
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Answer:
Step-by-step explanation:Let the no. be z , z+1 , z+2 , z+3
Addind all, we get, z+z+1+z+2+z+3
=4z + 6
ATQ, 4z + 6 = 136
=> z = 32.5
The largest no. is 32.5+3 = 35.5
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