Question

The sum of four consecutive odd natural numbers is 136. Find the largest of these numbers.

Answer 1

Answer:

let one number be x

then the second number be x + 2

and next number be x + 4

and next be x + 6

so, x + (x + 2) + (x + 4) + (x + 6) = 136

4x + 12 = 136

4x = 136 - 12

4x = 124

x = 124/4

x = 31

so, first number is 31

then second number is 31 + 2 = 33

then third number is 31 + 4 = 35

then the fourth number 31 + 6 = 37

hope it helps you very well

Answer 2

Answer: let one number be X

then the second number be X+2

And next number be X+4

And next be X+6

so , x + (x +2) + (x+4) + (x+6) = 136

4x + 12 =136

4x = 136 - 12

4x=124

x=124/4

x=31

so, first number is 31

then second number is 31 + 2 = 33

then third number is 31 + 4 = 35

then forth number is 31 + 6 = 37