the sum of four consecutive odd number is 488 what are the numbers
Answers
Answered by
2
Answer:
119,121,123,125
Step-by-step explanation:
x+x+2+x+3+x+4=488
4x+12=488
4x=476
x=476/4=121
Answered by
0
The required four consecutive numbers are 119, 121, 123, and 125.
Given:
The sum of four consecutive odd numbers is 488.
To Find:
The given numbers.
Solution:
Let us assume that 'x' is our first odd number. The next three consecutive odd numbers will occur at an interval of 2 from their preceding odd number.
Hence the four consecutive odd numbers at x, x+2, x+4, and x+6.
We are given that its sum equals 488.
⇒ x + (x+2) + (x+4) + (x+6) = 488
⇒ 4x + 12 = 488
⇒ 4x = 476
⇒ x = 476/4 = 119
Hence, the first odd number = 119.
The remaining numbers are x+2 = 121, x+4 = 123, and x+6 = 125.
∴ The required four consecutive numbers are 119, 121, 123, and 125.
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