Math, asked by sonamchubikharpon, 11 months ago

The sum of four consecutive odd number is 64. Find the prime numbers out of these numbers.​

Answers

Answered by Anonymous
3

Answer:

13, 17 and 19

Explanation:

Let the four consecutive odd number be 2x+1, 2x+3, 2x+5 and 2x+7.

Given that the sum of these numbers is 64.

\sf{\implies (2x+1)+(2x+3)+(2x+5)+(2x+7)=64}

\sf{\implies 8x+16=64}

\sf{\implies 8x = 48}

\bf{\therefore x = 6}

_____________

\sf{2x+1 = 2(6)+1=13}

\sf{2x+3 = 2(6)+3=15}

\sf{2x+5= 2(6)+5=17}

\sf{2x+1 = 2(6)+7=19}

Hence, the four consecutive odd numbers whose sum is 64 are 13, 15, 17 and 19.

Out of them the prime numbers are 13, 17 and 19.

Answered by halamadrid
0

Given; The sum of four consecutive odd numbers is 64.

To Find; the prime numbers out of these numbers.​

Solution; Let the four consecutive odd numbers as 2x+1,2x+3,2x+5,2x+7

sum =64

2x+1+2x+3+2x+5+2x+7=64

8x+16=64

8x=48

x=6

Odd numbers are 13,15,17,19

Hence the prime numbers as 13,17,19

#SPJ3

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