Question

the sum of four consecutive odd number is 80.Find the number​

Answer 1

Step-by-step explanation:

let the first number be x(odd no.)

the second no.is x+2

the third no.is x+4

the fourth no.is x+6

(x)+(x+2)+(x+4)+(x+6)=80

x+x+2+x+4+x+6=80

4x+12=80

4x=80-12

4x=68

x=68÷4

x=17

then the 4 consecutive odd no.s are 17 ,19,21,23

Answer 2

Answer:

17,19,21,23

Step-by-step explanation:

Given the sum of 4 consecutive odd number is 80

We have to the numbers

Let the first number be 'x', Second number be 'x+2'

Third number be 'x+4' , Fourth  number be 'x+6'

Sum = 80 (given)

⇒ x + x + 2 + x + 4 + x + 6 = 80

⇒ 4x + 12 = 80

⇒ 4x = 68

⇒ x = 17

Hence the first number is 'x' = 17

Second number is 'x+2' = 19

Third number is 'x+4' = 21

Fourth number is 'x+6' = 23