Math, asked by kirtikhubani387, 7 months ago

The sum of four consecutive odd numbers is 128. Find the numbers. *
1 point
29,31,33,35
39,41,43,45
19,21,23,25​

Answers

Answered by Vatsalchauhan40
0

Answer:

X=29

Step-by-step explanation:

X+X+2+X+4+X+6=128

4x+12=128

4x=128-12=116

X=116/4=29

Therefore, 29,31, 33&35 is answer

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Answered by divyanshugb
0

Answer:

Let four consecutive odd numbers be 2x + 1, 2x + 3, 2x + 5 and 2x + 7. According to the question,(2x + 1) + (2x + 3) + (2x + 5) + (2x + 7) = 128

→ 8x + (1 + 3 + 5 + 7) = 128

→ 8x + 16 = 128

→ 8x = 128 - 16

→ 8x = 112

→ 8x = 112/8

→ x = 14

∵ 2x + 1=(2 × 14) + 1 = 29, 2x + 3=(2 × 14) + 3 = 31,

2x + 5=(2 × 14) + 5 = 33, 2x + 7= (2 × 14) + 7 = 35

Hence, the required numbers are 29, 31, 33 and 35.

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