The sum of four consecutive odd numbers is 128. Find the numbers. *
1 point
29,31,33,35
39,41,43,45
19,21,23,25
Answers
Answered by
0
Answer:
X=29
Step-by-step explanation:
X+X+2+X+4+X+6=128
4x+12=128
4x=128-12=116
X=116/4=29
Therefore, 29,31, 33&35 is answer
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Answered by
0
Answer:
Let four consecutive odd numbers be 2x + 1, 2x + 3, 2x + 5 and 2x + 7. According to the question,(2x + 1) + (2x + 3) + (2x + 5) + (2x + 7) = 128
→ 8x + (1 + 3 + 5 + 7) = 128
→ 8x + 16 = 128
→ 8x = 128 - 16
→ 8x = 112
→ 8x = 112/8
→ x = 14
∵ 2x + 1=(2 × 14) + 1 = 29, 2x + 3=(2 × 14) + 3 = 31,
2x + 5=(2 × 14) + 5 = 33, 2x + 7= (2 × 14) + 7 = 35
Hence, the required numbers are 29, 31, 33 and 35.
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