Question

The sum of four consecutive odd numbers is 128.find the numbers​

Answer 1

Answer:

let the number be=X

so,four conservative odd number is X,(X+2),(X+4),(X+6).

X+X+2+X+4+X+6=28

4X +12=128

4x=128-12

X=116/4

X=29,X+2=31,X+4=33andx+6=35

Answer 2

Step-by-step explanation:

Let four consecutive odd numbers be 2x + 1, 2x + 3, 2x + 5 and 2x + 7.

According to the question,

(2x + 1) + (2x + 3) + (2x + 5) + (2x + 7) = 128

→ 8x + (1 + 3 + 5 + 7) = 128

→ 8x + 16 = 128

→ 8x = 128 - 16

→ 8x = 112

→ 8x = 112/8

→ x = 14

∵ 2x + 1=(2 × 14) + 1 = 29, 2x + 3=(2 × 14) + 3 = 31,

2x + 5=(2 × 14) + 5 = 33, 2x + 7= (2 × 14) + 7 = 35

Hence, the rewritten numbers are 29, 31, 33 and 35.