Question

The sum of four consecutive odd numbers is 80 find the numbers

Answer 1

let the numbers are X , (X+2), (X+4)

Opening brackets

x+X+2+x-2+X+4= 80

4x + 4 = 80

4x= 80 - 4

4X = 76

X= 76/4

X= 19

Now,

consecutive odd numbers are,

X=19

X+2= 19+2=21

x+2=19-2=17

X+4=19+4=23

Therefore number are 17,19,21,23

hope this helps

Answer 2

Answer:

Step-by-step explanation:

Given the sum of 4 consecutive odd number is 80

We have to the numbers

Let the first number be 'x', Second number be 'x+2'

Third number be 'x+4' , Fourth  number be 'x+6'

Sum = 80 (given)

⇒ x + x + 2 + x + 4 + x + 6 = 80

⇒ 4x + 12 = 80

⇒ 4x = 68

⇒ x = 17

Hence the first number is 'x' = 17

Second number is 'x+2' = 19

Third number is 'x+4' = 21

Fourth number is 'x+6' = 23