The sum of four consecutive term of an A. P. is 2. The sum of the third and The Fourth term is 11 find the term.
Answers
second term is 19
third term is 10
fourth term is 1
Answer:
Step-by-step explanation:
the four consicutive terms in AP are
a-d, a , a+d , a+2d
a-d + a+ a+d+a+2d =2
4a + 2d = 2
2a + d = 0. (divide by 2)
............( 1 )
The sum of 3rd and 4th term is 11
a+d + a+2d = 11
2a + 3d = 11
.........( 2 )
Substract equestion ( 1 ) and ( 2 )
2a + 3d = 11
2a + d = 0
- - -
_______________
0 2d = 10
D= 5
Put d = 5 in eq ( 2 )
2a + 3d =11
2a + 3*15 =11
2a + 15= 11
2a =11-15
2a = -4
a= -4
____
2
A= - 2
1st term is a-d = -2 -5
= -7
2nd term is a = -2
3rd term is a+d = -2+5
= 3
4th term is a +2d = -2+2*5
= -2+10
=8
The 1st consicutive term are -7, -2, 3,8
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