The sum of four consecutive term of an ap is 32 and their product is 3465
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let the consecutive terms be x,x+1,x+2,x+3
sum of this is(x)+(x+1)+(x+2)+(x+3)=32
x+x+1+x+2+x+3=32=>4x+6=32
=>4x=26=>x=6.5
(x)(x+1)(x+2)(x+3)=3465
x^4+6x^3+10x^2+5x
substitute X value value in above equation
(6.5)^4+6(6.5)^3+10(6.5)^2+5(6.5)
1785.0625+1647.75+422.5+32.5
3887.8125
sum of this is(x)+(x+1)+(x+2)+(x+3)=32
x+x+1+x+2+x+3=32=>4x+6=32
=>4x=26=>x=6.5
(x)(x+1)(x+2)(x+3)=3465
x^4+6x^3+10x^2+5x
substitute X value value in above equation
(6.5)^4+6(6.5)^3+10(6.5)^2+5(6.5)
1785.0625+1647.75+422.5+32.5
3887.8125
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