Question

The sum of four consecutive terms in increasing order is 72 . The ratio of product of 1st and 4th term to product of 2nd and 3rd term is 9:10 find the term ​

Answer 1

Answer: let a-3d , a-d , a+d and a+3d are four part of 72 which are in AP

so, a-3d +a-d +a +d +a+3d =72

4a = 72

a =18

now,

a/c to question,

(a -3d)(a+3d)/(a-d)(a+d) =9/10

(a^2 -9d^2)/(a^2-d^2) =9/10

10a^2 -90d^2 = 9a^2 -9d^2

a^2 = 81d^2

a = +_9d

d = +_a/d = +_18/9 =+_2

so,

number are -----

18-6 , 18-2, 18+2, 18+6

12 , 16 , 20, 24

or 24, 20, 16, 12

Answer 2

Answer:

REFFER TO THE ATTACHMENT