Question

The sum of four consecutive terms of an A.P. is 2. The sum of 3rd and 4th terms is 11. Find the terms.​

Answer 1

Answer:

a1 = - 7

a2 = -2

a3 = 3

a4 = 8

Step-by-step explanation:

four consecutive term = a + (a+d) + (a+2d) + (a+3d ) =2

= 4a + 6d = 2

= 2a + 3d = 1 --------(1)

The sum of 3rd and 4th terms is 11.

a + 2d + a + 3d = 11

2a + 5d = 11 -------(2)

subtract eq(1) from eq (2)

(2a+5d) - (2a+3d)= 11-1

2d= 10

d = 5

put in eq (1)

2a = -14

a = -7

a1= -7

a2= -2

a3 = -7+ 2×5

a3 = 3

a4 = -7 + 3×5

a4 = 8