Question

The sum of four consecutive terms of an ap is 32 and ratio of product of frst and last term to two middle terms is 7:15

Answer 1

let the four consecutive terms be a, a+d, a+2d, a+3d.

now according to question

a+a+d+a+2d+a+3d = 32

4a+6d = 32

2a+3d = 16

a=2 and d = 4

also a*(a+3d) / (a+d)*(a+2d) =7/15 (given in the question)

here also a=2 and d=4 satisfies the equation.

so the consecutive four terms are

a = 2

a+d=2+4=6

a+2d=2+2*4=10

and a+3d=2+3*4=14