the sum of four conseutive multiples of 5 is 330
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Hi...☺
Here is your answer...✌
Let the three consecutive multiples of 5 be x,x+5,x+10
ATQ,
x+x+5+x+10 = 330
3x+15 = 330
3x = 330-15
3x = 315
x = 315/3
x = 35
Hence the consecutive multiples are 35,40,45
Thank you ⭐
Here is your answer...✌
Let the three consecutive multiples of 5 be x,x+5,x+10
ATQ,
x+x+5+x+10 = 330
3x+15 = 330
3x = 330-15
3x = 315
x = 315/3
x = 35
Hence the consecutive multiples are 35,40,45
Thank you ⭐
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Answered by
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the series will be in arithmetic progression whose sum S=n/2(2a+(n-1)d)
n=no. of terms
a= initial term
d=common difference
putting these values , we get
330=4/2(2a+(4-1)×5)
165=2a+15
75=a
......hope it helps
n=no. of terms
a= initial term
d=common difference
putting these values , we get
330=4/2(2a+(4-1)×5)
165=2a+15
75=a
......hope it helps
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