Question

the sum of four number is 64.if 3 is added to the first number or 3 is subtracted from the second number or the third number is multiplied by 3 or the fourth number is divided by 3,then all the four numbers we would get are equal. What is the between the largest and smallest of the original number?
Pls explain it​

Answer 1

Answer:

let first number be x+3

second number be x-3

third number be 3x

fourth number be x/3

(x+3)+(x-3)+(3x)+(x/3)=64

x+3+x-3+3x+x/3=64

5x+x/3=64

16x/3=64

x/3=4

x=12

1st no.=15

2nd no. =9

3rd no. =36

4th no. =4

the number between the largest and smallest number=5 to 35

Answer 2

Let Frist number be x + 3

Second number be x - 3

third number be 3x

fourth number be x/3

(x + 3) + (x - 3) + (x/3) = 64

x +3 + x - 3 + 3x + x/3 = 64

5x + x/3 = 64

16 + x/3 = 64

x/3 = 4

x = 12

1 st number = 15

2 nd number = 9

3 rd number = 36

4th number = 4

Therefore the number between the largest and smallest number = 5 to 35.