Question

The sum of four numbers in A.P. is 26 and the sum of their squares is 214 find the numbers

Answer 1

Step-by-step explanation:

Let the four terms be

a1=a−3da1=a−3d

a2=a−da2=a−d

a3=a+da3=a+d

a4=a+3da4=a+3d

HERE WE HAVE TAKEN COMMON DIFFERENCE AS 2d2d

a1+a2+a3+a4=26a1+a2+a3+a4=26

4a=264a=26

a=6.5a=6.5

(a1a1)2+2+(a2a2)2+2+(a3a3)2+2+(a4a4)2=2142=214

(a−3d)2+(a−d)2+(a+d)2+(a+