Question

The sum of four numbers in AP is 26. The sum of squares of the first and the last number is greater
by 16 than the sum of squares of second and third. Find the numbers​

Answer 1

Step-by-step explanation:

Let the numbers be a−d,a,a+d

so 3a=27

⇒ a=9

Also (a−d)

2

+a

2

+(a+d)

2

=293.

3a

2

+2d

2

=293

d

2

=25

⇒ d=±5

therefore numbers are 4,9,14.