Question

The sum of four times a natural number and its square is 60.find the numbera

Answer 1

Step-by-step explanation:

here

4x+ x^2= 60

=> x^2+4x-60=0

=> x^2+10x-6x-60=0

=> x(x+10)-6(x+10)=0

=>(x+10)(x-6)=0

here

x= -10. (or) x = 6

hope it helps

Answer 2

let the number be x

according to the question,

x² + 4x = 60

x² + 4x - 60 = 0

x² - 6x + 10x - 60 = 0

x(x - 6) + 10(x - 6)

(x + 10) (x - 6)

x = -10, 6

since,

natural number cant be negative,

so,

Required number = 6