Question

the sum of four times a number and 5 gives a number 5 times of 8 make equation​

Answer 1

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HERE IS UR ANSWER

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r={-20} (decimal: -20.0)

PREMISES

4r=5(r+4)

ASSUMPTIONS

Let r=the number

CALCULATIONS

4r=5(r+4) (Expand the right side of the equation by distributing the common factor 5 over the two terms in the parentheses)

4r=5r+20

(4r-4r)-20=(5r-4r)+(20–20) (Isolate the “variables with coefficients” and the “constants” on opposite sides of the equation in order to simplify the solution)

0–20=r+0 (Flip the equation)

r+0=0–20

r=

-20 (decimal: -20.0)

PROOF

If r=-20, then the equations

4r=5(r+4)

4(-20)=5(-20+4)

4(-20)=5(-16) and

-80=-80 prove the root (zero) r=-20 of the mathematical proposition 4r=5(r+4)

Answer 2

Answer:

below is your answer

Step-by-step explanation:

According to question

According to question 4x+5=5x

According to question 4x+5=5x5x-4x=5 x=5

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