Question

The sum of four times the first number and three times the second number is 15. the difference of three times the first number and twice the second number is 7. fid the numbers.

Answer 1

Step-by-step explanation:

let first no is x and let the second no is y

a/q

4x+3y=15

and

3x-2y=7

after multiplying equation one by 3 and equation two by 4

we have

12x+9y=45

12x-8y=28

after subtracting equation two from equation one

we have

17y=17

therefore y=1

now putting the value of y in equation one

4x+3×1=15

4x+3=15

4x=12

therefore x =3