The sum of four times the first number and three times the
second number is 15. The difference of three times the first
number and twice the second number is 7. Find the numbers.
Answers
Answered by
0
Answer:
3,1,3,1
Step-by-step explanation:
four times of first number=3×4=12
three times of second number=1*3=3
their sum is =12+3=15
then
three times of first number =3*3=9
twice of second number =1*2=2
their difference is=9-2=7
Answered by
0
Answer:
x =3
y =1
Step-by-step explanation:
4x + 3y = 15
3x - 2y = 7
8x+ 6y = 30
9x - 6y= 21
________
17x = 51
--------------
x =3
y = 1
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