Question

the sum of frist term of an ap is 3nsq +6n .than find nth term of ap​

Answer 1

Sn = 3n^2 + 6n

S1 = 3 + 6 = 9

S1 = a1 = 9

S2 = 3( 2)^2 + 6( 2 ) = 12 + 12 = 24

S2 - S1 = a2

a2 = 24 - 9 = 15

Common difference, d = a2 - a1 = 15 - 9 = 6

nth term, An = a + ( n - 1) d

An = 9 + ( n - 1 ) × 6

An = 9 + 6n - 6

An = 6n + 3

Answer 2

Answer:

Step-by-step explanation: