The sum of hcf and lcm of two numbers is 403 and their lcm is 12 times their hcf. If one number is 93, then find the another number
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12x +x=403
13x=403, x=403/13=31
hcf=31,lcm=372
hcf×lcm =one no.× second no.
372×31=93×?
?=372×31/93 =124
second no.is 124
13x=403, x=403/13=31
hcf=31,lcm=372
hcf×lcm =one no.× second no.
372×31=93×?
?=372×31/93 =124
second no.is 124
Answered by
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given,
hcf=403
lcm=12times the hcf soo(12×403=4836)
one number=93(a)
second number be b
we know that ,
hcf+lcm=93×b
403+4836=93+b
403+4836/98=b
by solving we get,
455
hcf=403
lcm=12times the hcf soo(12×403=4836)
one number=93(a)
second number be b
we know that ,
hcf+lcm=93×b
403+4836=93+b
403+4836/98=b
by solving we get,
455
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