The sum of how many terms of the Ap 22,20,18... Will be zero?
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Sn = 0 ,a = 22, d= 20-22=-2
Sn= n/2(2a+(n-1)d
0 = n/2(44+(n-1)-2
0=n/2(44+(-2n+2)
0=44n-2n^2+2n
0=-2n^2+46n
2n^2=46n
n=23
so,the sum of 23 terms is 0
Hope it helps you!
Mark as brainliest!
Sn= n/2(2a+(n-1)d
0 = n/2(44+(n-1)-2
0=n/2(44+(-2n+2)
0=44n-2n^2+2n
0=-2n^2+46n
2n^2=46n
n=23
so,the sum of 23 terms is 0
Hope it helps you!
Mark as brainliest!
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