Question

The sum of infinite terms of 1/1.2 + 1/2.3 + 1/3.4 + ............... infinite is

Answer 1

Answer:

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Answer 2

Answer:

General term (n

th

term) =

n(n+1)

1

We can rewrite it as =

n(n+1)

n+1−n

=

n

1

−

n+1

1

Sum of n terms is

n=1

∑

n

[

n

1

−

n+1

1

]

=1+

2

1

+

3

1

+

4

1

+

n

1

.........−

2

1

−

3

1

−

4

1

−

n

1

−

n+1

1

=1−

n+1

1

Sum to infinity will get by putting n→∞

Then, 1−

n+1

1

=1−0=1 as n→∞

Step-by-step explanation:

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