Question

the sum of infinity of a g.p is 4/3 and the first term is 3/4 the common ratio is​

Answer 1

Step-by-step explanation:

which is the required ans.

Answer 2

Answer:

Common ratio, $r=\frac{7}{16}$

Step-by-step explanation:

In the given question,

Sum of infinite terms of a GP is = $\frac{4}{3}$

First term of the GP, a = $\frac{3}{4}$

Now,

Let us say the common ratio is given by 'r'.

So,

Also we know that,

The sum of infinite terms of a GP is given by,

$S=\frac{a}{1-r}$

So,

$\frac{4}{3} =\frac{\frac{3}{4}}{1-r}\\ So,\\4(1-r)=3\times \frac{3}{4}\\1-r=\frac{9}{16}\\r=\frac{7}{16}$

Therefore, the common ratio is given by,

$r=\frac{7}{16}$