Question

the sum of integers from 1 to 300 which is divisible by 2 or 5​

Answer 1

Given : integers from 1 to 300 which are divisible by 2 or 5​

To find : Sum of integers

Solution :

integers from 1 to 300

Divisible by 2  

2 , 4  , 6  , .........................................., 300

Sum

= 2+ 4  + 6  + .........................................+300

= 2(1 + 2 + 3 +.............................+ 150)

= 2 ( 150)(151)/2

= 22650

Divisible by 5

5 , 10  , 15  , .........................................., 300

Sum

= 5+ 10 + 15  + .........................................+300

= 5(1 + 2 + 3 +.............................+ 60)

= 5 (60)(61)/2

= 9150

Both contains number divisible by 10

Divisible by 10

 10  , 20  , .........................................., 300

Sum

=   10 +20  + .........................................+300

= 10(1 + 2 + 3 +.............................+ 30)

= 10 (30)(31)/2

= 4650

sum of integers from 1 to 300 which are divisible by 2 or 5​

= 22650 + 9150 - 4650

=27150

27150  is   sum of integers from 1 to 300 which are divisible by 2 or 5​

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Answer 2

Hi there!

$\bf\fbox\green{<em>Änswer </em><em> </em><em>=>}</em>$

❍ Given :- Sum of integers from 1 to 300.

❍ Solution :- Integers from 1 to 300

❍ Divisible by 2

2 , 4 , 6 ,———————————, 300

❍ Addition :-

2 + 4 + 6 + ———————————+ 300

2(1 + 2 + 3 +————————+ 150)

2(150)(151)/2

$\bf\red{22650}$

❍ Divisible by 5

5 , 10 , 15 , ——————————— , 300

❍ Addition :-

5 + 10 + 15 + ——————————+ 300

5(1 + 2 + 3 + ——————————+ 60)

5(60)(61)/2

$\bf\blue{9150}$

❍ Both numbers can be divisible by 10

❍ Divisibility by 10

10 , 20 , 30 , —————————— , 300

❍ Addition :-

10 + 20 + 30 + ————————— + 300

10(1 + 2 + 3 + —————————+ 30)

10(30)(31)/2

$\bf\pink{4650}$

So, the answer is 4650.

$\bf\fbox\purple{Be Brainly}$