Question

the sum of interior angles of a polygon is 3 times the sum of exterior angles . find the no. of sides

Answer 1

Hey

Here is your answer,

Sum of the exterior angles of a regular polygon is 3 times the sum of its exterior angles =360∘

∴ Sum of interior angles =3×360

Again we have sum of interior angles s=(n−2)180∘
Where n is the number of sides of the polygon

(n−2)180∘=1080∘

n−2=6

n=8

Hence the polygon of 8 sides is octagon

Hope it helps you!