Math, asked by ishaaryan2003, 10 months ago

The sum of interior angles of a polygon of 10 sides is……

Answers

Answered by sangeetabhatia0510
21

Answer:

1,440°

Step-by-step explanation:

A decagon is a 10-sided polygon, with 10 interior angles, and 10 vertices which is where the sides meet. A regular decagon has 10 equal-length sides and equal-measure interior angles. Each angle measures 144° and they all add up to 1,440° .

Answered by pulakmath007
14

The sum of interior angles of a polygon of 10 sides = 1440°

Given :

A polygon has 10 sides

To find :

The sum of interior angles of a polygon of 10 sides

Formula :

The sum of the measures of the interior angles of a polygon with n sides is (n – 2) × 180°

Solution :

Step 1 of 2 :

Write down number of sides

The polygon has 10 sides

So n = 2

Step 2 of 2 :

Find sum of interior angles

Hence sum of interior angles of a polygon of 10 sides

= ( 10 - 2 ) × 180°

= 8 × 180°

= 1440°

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. If ∠A and ∠B are two adjacent angles of a parallelogram. If ∠A = 70°, then ∠B = ?

https://brainly.in/question/18539197

2. The angles of the triangle are 3x–40, x+20 and 2x–10 then the value of x is

(a) 40 (b) 35 (c) 50 (d) 45

https://brainly.in/question/4194032

Similar questions