the sum of internal angle of a polygon is 5 times the sum of its external angle find the angles
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Sum of all interior angles of a polygon = (2n-4)90°
Sum of all exterior angles of a polygon = 360°
Given, (2n-4)90° = 5 x 360°
(2n-4) = 5 x 4
2n = 24
n = 12.
Sum of all exterior angles of a polygon = 360°
Given, (2n-4)90° = 5 x 360°
(2n-4) = 5 x 4
2n = 24
n = 12.
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