Math, asked by silnang96pam416, 10 months ago

the sum of largest 5 digit even positive integer and the smallest 5 digit odd negative integer​

Answers

Answered by HashtagNoName
4

Answer:

Largest 5 digit even positive integer is 99998

Smallest 5 digit odd negative integer is -10001

Sum of these two = 99998 + (-10001)

= 99998 - 10001

= 89997

Therefore, the answer is 89997

Answered by ItzLazyGirlThan
3

Step-by-step explanation:

largest 5 digit even number(positive)

=99,998

smallest 5 digit odd number(negative)

=-10,001

Sum=99,998+(-10,001)

=99998-10,001

=89997

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