the sum of lcm and hcf of two number is 7380 . if lcm of these number is 7340 more than hcf . find the product of two number
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Answered by
6
Let the LCM and HCF of two numbers be a and b respectively
a = b +7340 --------(1)
a+b = 7380
=> b+7340+b = 7380
=> 2b = 7380 - 7340
=> 2b = 40
=> b = 20
HCF = 20
LCM = 7360
Product of numbers = LCM *HCF
= 20 * 7360
= 147200
a = b +7340 --------(1)
a+b = 7380
=> b+7340+b = 7380
=> 2b = 7380 - 7340
=> 2b = 40
=> b = 20
HCF = 20
LCM = 7360
Product of numbers = LCM *HCF
= 20 * 7360
= 147200
Answered by
2
let LCM and HCF of two numbers are X&Y
X= Y+7340
X+ Y=7380
now Y+7340+Y=7380
2Y+7340=7380
2Y=7380-7340
2Y=40
Y=20
HCF= 20
LCM=7360
now
HCF×LCM=20×7360
=147200
•.•product of HCF and LCM is 147200
X= Y+7340
X+ Y=7380
now Y+7340+Y=7380
2Y+7340=7380
2Y=7380-7340
2Y=40
Y=20
HCF= 20
LCM=7360
now
HCF×LCM=20×7360
=147200
•.•product of HCF and LCM is 147200
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