Question

The sum of length, breadth and depth of a cuboid is 19 cm and the length of its diagonals is 11 cm. Find the surface area of the cuboid.

Answer 1

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Answer 2

HEY Buddy...!! here is ur answer

Answer : 240 cm²

Given that :

$l + b + h = 19 \\ \\ and \: \sqrt{ {l}^{2} + {b}^{2} + {h}^{2} } = 11 \\ \\ = > {l}^{2} + {b}^{2} + {h}^{2} = 121 \\ \\ = > ( {l + b + h)}^{2} - 2(lh + bh + lb) = 121 \\ \\ = > {(19)}^{2} - 2(lh + bh + lb) = 121 \\ \\ = > 361 - 2(lh + bh + lb) = 121 \\ \\ = > 2(lh + bh + lb) = 361 - 121 \\ \\ = > 2(lh + bh + lb) = 240$

So, the Total Surface Area of cuboid will be 240 cm²

I hope it will be helpful for you...!!

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