The sum of length ,breadth , and depth of a cuboid is 19cm and the lenght of its diagonal is 11cm .Find the surface area of cuboid
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Here's your answer...
Let the length, breadth and height be l, b, h respectively.
l+b+h = 19 cm
(l²+b²+h²)^½ = 11 cm
By the identity of (a+b+c)²...
(l+b+h)² = l²+b²+h² + 2(lb+bh+hl)
361 = 121 + 2(lb+bh+hl)
2(lb+bh+hl) = 240
Since 2(lb+bh+hl) = surface area of cuboid...
Surface area = 240 cm²
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Here's your answer...
Let the length, breadth and height be l, b, h respectively.
l+b+h = 19 cm
(l²+b²+h²)^½ = 11 cm
By the identity of (a+b+c)²...
(l+b+h)² = l²+b²+h² + 2(lb+bh+hl)
361 = 121 + 2(lb+bh+hl)
2(lb+bh+hl) = 240
Since 2(lb+bh+hl) = surface area of cuboid...
Surface area = 240 cm²
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