the sum of length, breadth and height of a cuboid is 21cm and the length of its diagonal is root 149 cm, then find the surface area of the cuboid.
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Answer:
292 cm^2
Step-by-step explanation:
1. l + b + h = 21
2. l^2 + b^2 + h^2 = d^2 = (√149)^2
3. 2(lb + bh + hl) = Surface area of cuboid
Using the algebraic identity,
4. (l + b+ h)^2 = l^2 + b^2 + h^2 + 2(lb + bh + hl)
Squaring on both sides of equation 1.
5. (l + b + h)^2 = 441
Substituting the value of (l + b+ h)^2 and l^2 + b^2 + h^2 from equation 5. and 2. in equation 4. ,
441 = 149 + 2(lb + bh + hl)
Now from equation 3.
441 = 149 + Surface area of cuboid
Surface area of cuboid = 441 - 149 = 292 cm^2
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