the sum of length breadth and height of a cuboid is 38 cm and its diagonal is 22 cm then find its total surface area
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Let the length, breadth and height of the cuboid be l cm, b cm and h cm respectively.
l+b+h=38-----------------[1]
Now, diagonal=22
√l²+b²+h²=22
l²+b²+h²=484---------------[2]
now,l+b+h=38
so,Squaring both sides, we get
(l + b + h)²=38²
l²+b²+h²+2lb+2bh+2lh=1444
484+2[lb+bh+lh]=1444
2[lb+bh+lh]= 1444-484=960 cm²
l+b+h=38-----------------[1]
Now, diagonal=22
√l²+b²+h²=22
l²+b²+h²=484---------------[2]
now,l+b+h=38
so,Squaring both sides, we get
(l + b + h)²=38²
l²+b²+h²+2lb+2bh+2lh=1444
484+2[lb+bh+lh]=1444
2[lb+bh+lh]= 1444-484=960 cm²
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