Question

the sum of length, breadth, depth of a cuboid is 10cm and its diagonal is 4√2cm. Find its surface area?​

Answer 1

Answer:

But surface area of cubiod is 2( lb+bh+lb)

Surface area of cubiod 240

Answer 2

Answer:

$using \: identity \: of \: algebraic : \\ {(a + b + c)}^{2} \\ = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca \\ where \\ a = lenght \\ b = breadth \\ c =depth \\ {diagonal}^{2} = {a}^{2} + {b}^{2} + {c}^{2} = {(4 \sqrt{2} )}^{2} \\ 32 \\ (a + b + c) = 10 \\ 2ab + 2bc + 2ca = surface \: area \\ {10}^{2} = 32 + surface \: area \\ surface \: area \: = 100 - 32 \\ 68 \: {cm}^{2}$