Question

the sum of length of a rectangle is three by fourth of its perimeter if the perimeter is 160 cm find the length and breadth of rectangle​

Answer 1

Step-by-step explanation:

2L=3/4P

2L=3/4×160

2L=120

L=120/2

L=60

P=2(L+B)

160=2(60+B)

160/2=60+B

80-60=B

20=B

so,L=60cm;B=20cm

Answer 2

The length and breadth of the given rectangle is 60 cm and 20 cm respectively.

• Let the length of the rectangle be l, and the breadth be b.

• Given,

Perimeter of the rectangle = 160 cm

We know that the perimeter of a rectangle is given by 2(l + b).

Therefore,  2(l + b) = 160 cm    - (i)

• A rectangle has two sides of length.

Therefore, the sum of its length = l + l = 2l

• According to the question,

2l = (3/4) × 160 cm

Or, 2l = (3 × 160 cm) / 4

Or, 2l = 120 cm

Or, l = (120 cm) / 2

Or, l = 60 cm

• Putting l = 60 cm in equation (i), we get,

2 (60 cm + b) = 160 cm

Or, (2 × 60 cm) + 2b = 160 cm

Or, 120 cm + 2b = 160 cm

Or, 2b = 160 cm - 120 cm

Or, 2b = 40 cm

Or, b = (40 cm) / 2

Or, b = 20 cm

• Therefore, l = 60 cm and b = 20 cm.