Question

the sum of magnitude of two forces acting at a point is 16 Newton if the resultant force is 8 Newton and its direction is perpendicular to small Air force then the forces​

Answer 1

Let the smaller of the two forces is of magnitude be

F

N.

Hence the larger one will be

(

16

−

F

)

N. As the resultant

8

N is perpendicular to

F

we can write.

F

2

+

8

2

=

(

16

−

F

)

2

⇒

(

16

−

F

)

2

−

F

2

=

64

⇒

16

(

16

−

2

F

)

=

64

⇒

256

−

32

F

=

64

⇒

F

=

256

−

64

32

=

6

N

So the smaller force is

6

N

and the larger force is

10

N

Hope it helps.....thank uu

Answer 2

Answer:

6N is smaller force and 10N is greater force

Explanation:

Let to forces be X and Y, then

X+Y= 16. (1)

and

Y² = 8² + X²

(16-X)² = 64 + X²

256 + X² -32X = 64 + X²

192 = 32X

X = 6N

Now, from equation (1)

Y = 10N