The sum of magnitude of two forces acting atpoint
is 16
if their resultant is perpendicular to smallenr
forces Magnitude 8N then find forces.
Answers
Answered by
0
Answer:
6N and 10N
Explanation:
A+B=16...(1)
tanα=
A+Bcosθ
Bsinθ
=tan90
Thus, A+Bcosθ=0⇒cosθ=−
B
A
...(2)
We also have: 8=
A
2
+B
2
+2ABcosθ
...(3)
Solving these we get, A=6N and B=10N
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Answered by
1
6N and 10N
A+B=16...(1)
tanα=
A+Bcosθ
Bsinθ
=tan90
Thus, A+Bcosθ=0⇒cosθ=−
B
A
...(2)
We also have: 8=
A
2
+B
2
+2ABcosθ
...(3)
Solving these we get, A=6N and B=10N
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