Question

The sum of magnitudes of two forces acting at a point is 16 N. If their resultant is normal to the
smaller force and has a magnitude of 8 N, the forces are [ ]

a) 2 N, 4N b) 3N, 6 N c) 6N, 10 N d) 7 N, 14 N​

Answer 1

Explanation:

Let smaller magnitude be FN

Hence the larger one will be (16-F)N.

F^2-8^2=(16-F)^2

=(6-F)^2-F^2=64

=16(16-2F)=64

=256-32F=64

F=256-64/32=6N

So

the smaller magnitude is 6N

and

the larger magnitude is 10N.