Question

the sum of magnitudes of two forces acting at a point is 16 N .If their resultant is normal to the smaller force and has a magnitude of 8N. Then the forces are​

Answer 1

Answer:

Answer

Correct option is

A

6N and 10N

A+B=16...(1)

tanα=

A+Bcosθ

Bsinθ

=tan90

Thus, A+Bcosθ=0⇒cosθ=−

B

A

...(2)

We also have: 8=

A

2

+B

2

+2ABcosθ

...(3)

Solving these we get, A=6N and B=10N