the sum of magnitudes of two forces acting at a point is 16 N .If their resultant is normal to the smaller force and has a magnitude of 8N. Then the forces are
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Correct option is
A
6N and 10N
A+B=16...(1)
tanα=
A+Bcosθ
Bsinθ
=tan90
Thus, A+Bcosθ=0⇒cosθ=−
B
A
...(2)
We also have: 8=
A
2
+B
2
+2ABcosθ
...(3)
Solving these we get, A=6N and B=10N
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