The sum of magnitudes of two forces acting at a point is 40 kg.wt. the magnitude of their resultant is 20 kg.wt. and it is perpendicular to the smaller force. Find the magnitude of each of the two forces and the cosine of the angle between them.
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Answer:
A+B=16...(1)
tanα=
A+Bcosθ
Bsinθ
=tan90
Thus, A+Bcosθ=0⇒cosθ=−
B
A
...(2)
We also have: 8=
A
2
+B
2
+2ABcosθ
...(3)
Solving these we get, A=6N and B=10N
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